(u-5)^2=2(u^2)-2u+40

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Solution for (u-5)^2=2(u^2)-2u+40 equation: 



(u-5)^2=2(u^2)-2u+40

We move all terms to the left:

(u-5)^2-(2(u^2)-2u+40)=0

We get rid of parentheses

-2u^2+(u-5)^2+2u-40=0

We add all the numbers together, and all the variables

-2u^2+2u+(u-5)^2-40=0

We move all terms containing u to the left, all other terms to the right

-2u^2+2u+(u-5)^2=40

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